Results: 1580
Notes
  • Newest first
  • Oldest first
  • Newest first(All)
  • Oldest first(All)
RPS
echo rps("Rock", "Paper")."\n";
echo rps("Scissor", "Paper")."\n";
echo rps("Paper", "Paper")."\n";

function rps($p1, $p2){
	$res= "";
	if ($p1==$p2){
		$res="It's a draw";
	}else if (
		($p1=="Paper" && $p2=="Rock")||
		($p1=="Rock" && $p2=="Scissor")||
		($p1=="Scissor" && $p2=="Paper")
		){
			$res="Player 1 wins";
		}else {
			$res="Player 2 wins";
		}
		return $res;
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
print_r(splitCode("TEWA8392")); // ➞ ["TEWA", 8392]
print_r(splitCode("MMU778")); // ➞ ["MMU", 778]
print_r(splitCode("SRPE5532")); // ➞ ["SRPE", 5532]


function splitCode($code) {
	$alpha = $numbers = '';
	$len = strlen($code);
	for ($i=0; $i<$len; $i++) {
		if(!(47 < ord($code[$i])&&ord($code[$i]) < 58)) {
		// if(!is_numeric($code[$i])) {
			$alpha.=$code[$i];
		} else {
			$numbers = substr($code, $i);
			break;
		}
	}
	return [$alpha, $numbers];
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
0
//An array is special if every even index contains an even number and every odd index contains an odd number. 
var_dump(isSpecialArray([2, 7, 4, 9, 6, 1, 6, 3]));//➞ true
var_dump(isSpecialArray([2, 7, 9, 1, 6, 1, 6, 3]));//➞ false
var_dump(isSpecialArray([2, 7, 8, 8, 6, 1, 6, 3]));//➞ false

function isSpecialArray($array){
	foreach($array as $key=>$value){
		if($key%2+$value%2==1){
			return "Array is not special";
		}
	}
	return "Array is special";
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
echo correctSpacing_1(" my   name   is Slim Shady  ")."\n";
echo correctSpacing_2(" my   name   is Giovani Giorgio  ")."\n";

//Using explode function
function correctSpacing_1($sentence) {
	$array = explode(' ', $sentence);
	$count = count($array);
	for ($i = 0; $i < $count; $i++) {
		if (!$array[$i]) {
			unset ($array[$i]);
		}
	}
	return implode(' ', $array);
}

//Using while loop
function correctSpacing_2($sentence) {
	$sentence = trim($sentence);
	while (str_contains($sentence, '  ')) {
		$sentence = str_replace('  ', ' ', $sentence);
	}
	return $sentence;
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
var_dump(isValidHexCode("#CD5C5C")); // ➞ true
var_dump(isValidHexCode("#EAECEE")); // ➞ true
var_dump(isValidHexCode("#eaecee")); // ➞ true
var_dump(isValidHexCode("#CD5C58C")); // ➞ false
// Length exceeds 6
var_dump(isValidHexCode("#CD5C5Z")); // ➞ false
// Not all alphabetic characters in A-F
var_dump(isValidHexCode("#CD5C&C")); // ➞ false
// Contains unacceptable character
var_dump(isValidHexCode("CD5C5C")); // ➞ false
// Missing #


function isValidHexCode($code) {
	$allowed = '0123456789abcdef';
	$len = strlen($code);
	if ($len!=7 || $code[0]!='#') {
		return false;
	}
	for ($i=1; $i<$len; $i++) {
		if (!str_contains($allowed, strtolower($code[$i]))) {
			return false;
		}
	}
	return true;
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
echo century(1756)."\n";
echo century(1555)."\n";
echo century(1000)."\n";
echo century(1001)."\n";
echo century(2005)."\n";


// Get the Century
function century($year) {
	$suf = 'th';
	if ($year > 2000) {
		$suf = 'st';
	}
	return ceil($year/100).$suf.' century';
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
print_r(findPrimeNumbers(50));

//Prime numbers are evenly divided by themselves and by one
//Finds first N prime number
function findPrimeNumbers($n){
	$num=2;//first  prime number is 2
	$res=[];
	while  (0<$n){
		$cnt=0;
		for ($i=2; $i<=$num; $i++){
			if ($num%$i==0){
				$cnt++;
			}
		}
		if ($cnt==1){
			$res[]=$num;
			$n--;
		}
		$num++;
	}
	return $res;
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
echo "6 - ".checkNumber(6)."\n\n";
echo "9 - ".checkNumber(9)."\n\n";
echo "12 - ".checkNumber(12)."\n\n";

function checkNumber($num) {
	$res = 'Deficient';

	if ($num == 1) {
		return false;
	}

	$sqrt = sqrt($num);

	$sum = 1;
	// Loops starting 2 to the square root of the given number
	for ($i = 2; $i <= $sqrt; $i++) {
		if ($num%$i == 0) {
			$sum += $i;

			$result = $num/$i;
			// If $i is not equal to the square root,
			// then adds it to the $sum variable
			if ($result != $i) {
				$sum += $result;
			}
		}
	}
	if ($sum == $num) {
		$res = 'Perfect';
	} else if ($sum > $num) {
		$res = 'Abundant';
	}
	return $res;
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
<?php
echo convertKilometersToMiles(56)."\n";
echo convertMilesToKilometers(265.56)."\n";

function convertKilometersToMiles($km){
$mile = 0.621371;
return $km * $mile;
}

function convertMilesToKilometers($miles){
$one_miles = 0.621371;
return $miles * $one_miles;
}
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
echo libraryFine_3(10, 7, 2015, 7, 7, 2015)."\n\n";
echo libraryFine_3(10, 8, 2015, 5, 3, 2015)."\n\n";
echo libraryFine_3(10, 7, 2017, 5, 7, 2015)."\n\n";
echo libraryFine_3(10, 7, 2017, 10, 7, 2017)."\n\n";

//Using if and else if functions
function libraryFine($d1, $m1, $y1, $d2, $m2, $y2) {
	$hacks = 0; //fine unit hackos
	$a = $d1-$d2;
	$b = $m1-$m2;
	$c = $y1-$y2;

	if ($a == 0 && $b == 0 && $c == 0) {
		$hacks = 0;
	} else {
		if ($a != 0) {
			$hacks = 15*$a;
		}if ($b != 0) {
			$hacks = 500*$b;
		}if ($c != 0) {
			$hacks = 10000;
		}
		return $hacks;
	}
}  //This is my idea, maybe good, maybe not so


//Using switch function
function libraryFine_2($d1, $m1, $y1, $d2, $m2, $y2) {
	$hacks = 0;
	$a = $d1-$d2;
	$b = $m1-$m2;
	$c = $y1-$y2;

	switch ($hacks) {
		case ($a == 0 && $b == 0 && $c == 0):
			$hacks = 0;
			break;
		case ($a != 0):
			$hacks = 15*$a;
			break;
		case ($b != 0):
			$hacks = 500*$b;
			break;
		case ($c != 0):
			$hacks = 10000;
			break;
	}
	return $hacks;
}  // doesn't work

// Calculates the fine, if the book is returned late
function libraryFine_3($d1, $m1, $y1, $d2, $m2, $y2) {
    
    $hacks = 0;
    
    // If the book is returned after the calendar 
    // year, there is a fixed fine of 10,000 Hackos
    if ($y1 > $y2) {
        $hacks = 10000;
    } 
    
    // If the book is returned after the expected return 
    // month but still within the same calendar year
    else if ($m1 > $m2  &&  $y1 == $y2) {
        $hacks = 500 * ($m1 - $m2);
    }
    
    // If the book is returned after the expected return 
    // day but still within the same calendar month and year
    else if ($d1 > $d2  &&  $m1 == $m2  &&  $y1 == $y2) {
        $hacks = 15 * ($d1 - $d2);
    }
    return $hacks;
} //fastets solution
by ვაჟა ტყემალაძე
2 years ago
0
PHP
Problem Solving
Note
php
Problem
0
Results: 1580