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Comparison between PHP and JS "problem solving" moduls (3) CODE 
// Make the array in JS
const array = [0, 1, 2];
array[4] = 4;
console.log(array[3]);
// outputs "undefined"
/* at the third index the array will get the value "undefined" because the value - 4 will be placed at the fourth index and the code will not skip the third index */
// Make the array in PHP
$arr = [0, 1, 2];
$arr[4] = 4;
echo $arr[3];
// unlike JS, that code will not returns anything, there is nothing in 3rd index.
// another interesting fact about it console.log(array.length); // in JS echo (count($arr)); // in PHP // returns 5 in JS and 4 in PHP because in JS the 3rd index got the value - "undefined", but in PHP it just skipped the 3rd index and took the 4th position.
by Luka Khitaridze
3 years ago
0
JavaScript
PHP
Array difference
0
Difference between while and do while loop CODE
/* The main difference between both loops is that while loop checks the condition at the beginning, whereas do-while loop checks the condition at the end of the loop */ 
// make the while loop example
$i = 1;
while ($i < 5) {
    echo "the result is $i", "\n";
    $i++;
    }
// please note, If the condition never becomes false, the statement will continue to execute indefinitely.
// make the do...while loop
$i = 1;
do {
echo "hello world";
}
while ($i < 0);
// is that case will return the result?
/* Note that in a do while loop, the condition is tested AFTER executing the statements within the loop. This means that the do while loop would execute its statements AT LEAST ONCE, EVEN IF THE CONDITION IS FALSE the first time */ // Therefore it returns "hello world" only one time
by Luka Khitaridze
3 years ago
0
PHP
LOOPS
0
switch operator
$age = 9; switch($age){ case $age < 12: echo 'u are child'; break; case $age > 12 && $age <19: echo 'u are teen'; break; case $age > 20: echo 'u are an adult'; break; }
by guga muchiashvili
3 years ago
0
PHP
php note
0
Hello world CODE
Prints the text 
Hello world
echo "Hello world";
Prints the two words one by one
echo "Hello ";
echo "world";
Prints the variable 
$greeting
$greeting = "Hello world";
Echo $greeting;
Concatenates the string to the variable 
$greeting
$greeting = "hello world!";
Echo $greeting . " Let's get started!";
by Valeri Tandilashvili
3 years ago
11
PHP
echo / print
4
Comparison between PHP and JS "problem solving" moduls (2) CODE 
const a = 10 + '20';                 // the sum of integer and string values
const b = '20' + '20';                   // the sum of two string values
console.log(a, b);                       // returns "1020" , "2020" 
console.log(typeof(a, b));          // both are strings
$a = 10 + '20';                          // The sum of an integer and a string
$b = '1020' + '20';                        // The sum two strings
echo $a, "\n ", $b, "<br>";         // returns 30, 1040 
echo var_dump($a, $b);            // both are integers (int+str) (str+str)
/* When you try to perform math operations with strings in PHP, they are cast to approprite type. In this case to int. But you can cast integer back to string in the below example */ 
$integer = 10;
$stringIncrement = '20';
$result = $integer + $stringIncrement;
$result = (string) $result;
var_dump($result);
by Luka Khitaridze
3 years ago
0
JavaScript
PHP
Integer
String
0
strict requirement
PHP automatically associates a data type to the variable, depending on its value. Since the data types are not set in a strict sense, you can do things like adding a string to an integer without causing an error. In PHP 7, type declarations were added. This gives us an option to specify the expected data type when declaring a function, and by adding the strict declaration, it will throw a "Fatal Error" if the data type mismatches. 
<?php declare(strict_types=1); // strict requirement

function addNumbers(int $a, int $b) {
  return $a + $b;
}
echo addNumbers(5, "5 days");
// since strict is enabled and "5 days" is not an integer, an error will be thrown
?>
by Guram Azarashvili
3 years ago
0
PHP
PHP official doc
0
Array 
<!DOCTYPE html>
<html>
<body>

<?php

$students_inf = array(
array(
	
        "Name" => 'Luka', 
	"Age" => 21,
	"E-mail" => 'Luka.N111@gmail.com',
	"Status" => 'Registered'

  ),    
	
     array(
	"Name" => 'Nini',	
	"Age" => 20,
	"E-mail" => 'Nini.K312@gmail.com',
	"Status" => 'Unregistered'
		
  ),
		
     array(
   	"Name" => 'Giorgi',
        "Age" => 22,
        "E-mail" => 'Giorgi.ES8@gmail.com',     
   	"Status" => "Registered"
   	
   	)
 );
  
 //You can get students information with echo and var_dump. 
 
 var_dump(json_encode($students_inf));
 
 echo str_repeat("<br />",5);
 
 
 echo $students_inf[0]['Name']. "<br />";
 echo $students_inf[0]['Age']. "<br />";
 echo $students_inf[1]['Status']. "<br />";  
 echo $students_inf[2]['E-mail']. "<br />"; 

  
 ?>

</body>
</html>
by ნუგო ყველაშვილი
3 years ago
0
PHP
array
php
0
Variable scope
A variable declared outside a function has a GLOBAL SCOPE and can only be accessed outside a function. A variable declared within a function has a LOCAL SCOPE and can only be accessed within that function: 
<?php
$name='GURAM';//Global variable
function local_var() {
    $name='guram'; //local variable
    echo  'Local variable: '.$name ."\n";
  }
local_var();
echo 'Global variable: '.$name;
?>
"static" Normally, when a function is completed/executed, all of its variables are deleted. However, sometimes we want a local variable NOT to be deleted. We need it for a further job. To do this, use the static keyword when you first declare the variable: 
<?php
function myTest() {
  static $x = 0;
  echo $x;
  $x++;
}

myTest();
myTest();
myTest();
?>
by Guram Azarashvili
3 years ago
0
PHP
0
User Defined Function in PHP
A user-defined function declaration starts with the key-word 
function
: 
function FUNCTIONNAME() {
  code to be executed;
}
by Eka Suarishvili
3 years ago
0
PHP
0
variable math
<?php $x = 30; $y = 10; function myTest() { global $x, $y; $y = $x / $y; } myTest(); echo $y; // outputs 15 ?>
by Luka Okujava
3 years ago
0
PHP
1
Results: 1578