Results: 1578
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zip / unzip file or folder
Zips .sql file
db_backup.sql
and locates it to
public_html/
directory
zip -r db_backup.sql public_html/
Unzips the file
zipped.zip
and puts it to the current directory
unzip zipped.zip
by Valeri Tandilashvili
4 years ago
0
Linux
0
for example we want to sort this
$users
array according to
"score"
value
$users = array(
    [
        'id' => 1, 
        'name' => 'vighac tipovichi', 
        'score' => 90
    ],
    [
        'id' => 2, 
        'name' => 'sxva tipson', 
        'score' => 100
    ],

);
__________________________________________ 1st method is using this custom function:
array_sort($users, 'score', SORT_DESC)
function array_sort($array, $on, $order=SORT_ASC){
    $new_array = array();
    $sortable_array = array();

    if (count($array) > 0) {
        foreach ($array as $k => $v) {
            if (is_array($v)) {
                foreach ($v as $k2 => $v2) {
                    if ($k2 == $on) {
                        $sortable_array[$k] = $v2;
                    }
                }
            } else {
                $sortable_array[$k] = $v;
            }
        }


        switch ($order) {
            case SORT_ASC:
                asort($sortable_array);
            break;
            case SORT_DESC:
                arsort($sortable_array);
            break;
        }

        foreach ($sortable_array as $k => $v) {
            $new_array[$k] = $array[$k];
        }
    }
  return $new_array;
}
__________________________________________ 2nd method is by using
usort
built-in function which allows us to use "user defined" callback/function to sort array: 1.either by declaring another function dedicated to sort array as you wish
function custom_sort_users($a, $b) {
        if ($a['score'] == $b['score']) {
                return 0;
        }
        return ($a['score'] > $b['score']) ? -1 : 1;
}
usort($users, "custom_sort_users");
2.or using callback:
usort($users, function($a, $b){
    if ($a['score'] == $b['score']) {
            return 0;
    }
    return ($a['score'] > $b['score']) ? -1 : 1;
});
by გიორგი უზნაძე
4 years ago
0
PHP
Arrays
0
disable safe update
# Disables safe update temporarily 
SET SQL_SAFE_UPDATES = 0;

# Updates multiple rows at once
UPDATE notes SET priority = 100 WHERE priority = 0;

# Enables safe update
SET SQL_SAFE_UPDATES = 1;
by Valeri Tandilashvili
4 years ago
0
MySQL
alter
1
Find duplicate values in one column:
SELECT 
    email, 
    COUNT(email) AS cnt
FROM
    contacts
GROUP BY email
HAVING cnt > 1;
Find duplicate values in multiple columns:
SELECT 
    first_name, COUNT(first_name) as cnt_fn,
    last_name,  COUNT(last_name)  as cnt_ln,
    email,      COUNT(email)  as cnt_m
FROM
    users
GROUP BY 
    first_name , 
    last_name , 
    email
HAVING  cnt_fn > 1
    AND cnt_ln > 1
    AND cnt_m > 1;
by Luka Tatarishvili
4 years ago
3
MySQL
Select
1
MySQL row count of a single table:
SELECT 
    COUNT(*)
FROM
    customers;
MySQL row count of two or more tables:
SELECT 
    'customers' tablename, 
     COUNT(*) rows
FROM
    customers 
UNION 
SELECT 
    'orders' tablename, 
     COUNT(*) rows
FROM
    orders;
by Luka Tatarishvili
4 years ago
0
MySQL
Select
0
ALTER TABLE
Adds column
personal_id
after
api_method
column in
requests
table
ALTER TABLE requests
ADD COLUMN personal_id VARCHAR(15) AFTER api_method;
If we run the same
alter
statement one more time, we will get the following error with code
1060
Error Code: 1060. Duplicate column name 'personal_id'
If we want to delete a column from a table, we use the following command
ALTER TABLE `requests` 
DROP COLUMN `status_id`;
by Valeri Tandilashvili
4 years ago
0
MySQL
alter
2
MySQL JOIN Types
SELECT from two tables
SELECT * FROM Table1;
SELECT * FROM Table2;
INNER JOIN
SELECT *
 FROM Table1 t1
INNER JOIN Table2 t2
   ON t1.fk = t2.id;
LEFT OUTER JOIN
SELECT *
 FROM Table1 t1
LEFT OUTER JOIN Table2 t2
 ON t1.fk = t2.id;
RIGHT OUTER JOIN
SELECT *
 FROM Table1 t1
RIGHT OUTER JOIN Table2 t2
 ON t1.fk = t2.id;
SEMI JOIN – Similar to INNER JOIN, with less duplication.
SELECT *
FROM Table1 t1
WHERE EXISTS (SELECT 1
               FROM Table2 t2
               WHERE t1.fk = t2.id
            );
ANTI SEMI JOIN
SELECT *
FROM Table1 t1
WHERE NOT EXISTS (SELECT 1  
                   FROM Table2 t2
                   WHERE t1.fk = t2.id
                );
LEFT OUTER JOIN with exclusion
SELECT *
 FROM Table1 t1
LEFT OUTER JOIN Table2 t2
  ON t1.fk = t2.id
WHERE t2.id is null;
RIGHT OUTER JOIN with exclusion
SELECT *
 FROM Table1 t1
RIGHT OUTER JOIN Table2 t2
  ON t1.fk = t2.id
WHERE t1.fk is null;
FULL OUTER JOIN
SELECT * FROM Table1 t1
 LEFT OUTER JOIN Table2 t2
  ON t1.fk = t2.id
UNION
SELECT * FROM Table1 t1
 RIGHT OUTER JOIN Table2 t2
  ON t1.fk = t2.id;
FULL OUTER JOIN with exclusion
SELECT * FROM Table1 t1
 LEFT OUTER JOIN Table2 t2
  ON t1.fk = t2.id
 WHERE t2.id IS NOT NULL
UNION
SELECT * FROM Table1 t1
 RIGHT OUTER JOIN Table2 t2
  ON t1.fk = t2.id
 WHERE t1.ID IS NOT NULL;
Two INNER JOINs
SELECT *
 FROM Table1 t1
INNER JOIN Table2 t2
  ON t1.fk = t2.id
INNER JOIN Table3 t3
  ON t1.fk_table3 = t3.id;
Two LEFT OUTER JOINS
SELECT *
 FROM Table1 t1
LEFT OUTER JOIN Table2 t2
  ON t1.fk = t2.id
LEFT OUTER JOIN Table3 t3
  ON t1.fk_table3 = t3.id;
INNER JOIN and a LEFT OUTER JOIN
SELECT *
 FROM Table1 t1
INNER JOIN Table2 t2
  ON t1.fk = t2.id
LEFT OUTER JOIN Table3 t3
  ON t1.fk_table3 = t3.id;
by გიორგი ბაკაშვილი
4 years ago
0
MySQL
JOIN
2
database size in MYSQL
The following query can show the size (GB) of all the database in a table view :
SELECT table_schema "database", sum(data_length + index_length)/1024/1024/1024 "size in GB"
FROM information_schema.TABLES GROUP BY table_schema;
The following query can show the size (MB) of all the database in a table view :
SELECT table_schema 'database', ROUND(SUM(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB"
FROM information_schema.tables
GROUP BY table_schema;
The following query can show only the size of a specific database:
SELECT table_schema,
ROUND(SUM(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB"
FROM information_schema.tables WHERE table_schema='DB_NAME'
GROUP BY table_schema ;
The following query can show total tables, the total table row, DB size of a specific database:
SELECT TABLE_SCHEMA AS DB_Name, count(TABLE_SCHEMA) AS Total_Tables, 
SUM(TABLE_ROWS) AS Total_Tables_Row, 
ROUND(sum(data_length + index_length)/1024/1024) AS "DB Size (MB)", ROUND(sum( data_free )/ 1024 / 1024) AS "Free Space (MB)"
FROM information_schema.TABLES
WHERE TABLE_SCHEMA = 'DB_NAME'
GROUP BY TABLE_SCHEMA ;
by გიორგი ბაკაშვილი
4 years ago
0
MySQL
0
copy text to clipboard from Dom Element
<div id="some-id">Text to copy</div>
copyToClipboard('some-id');
function copyToClipboard(containerid) {
  if (document.selection) {
    let range = document.body.createTextRange();
    range.moveToElementText(document.getElementById(containerid));
    range.select().createTextRange();
    document.execCommand("copy");
  } else if (window.getSelection) {
    let range = document.createRange();
    range.selectNode(document.getElementById(containerid));
    window.getSelection().removeAllRanges();
    window.getSelection().addRange(range);
    document.execCommand("copy");
    window.getSelection().removeAllRanges();
  }
}
by გიორგი უზნაძე
4 years ago
0
JavaScript
DOM
3
Javascript "inArray" alternative for php "in_array" function
returns
true
if
needle
is found inside
 haystack
inArray('find_me', ['text1', 'text2', 'find_me', 'text3']);
returns true
function inArray(needle, haystack) {
  var length = haystack.length;
  for(var i = 0; i < length; i++) {
      if(haystack[i] === needle) { return true };
  }
  return false;
}
by გიორგი უზნაძე
4 years ago
0
JavaScript
PHP Alternatives
2
Results: 1578